Compound ‘X’ with molecular formula C4H9Br reacts with aqueous KOH to give an alcohol. The rate of t

Compound ‘X’ with molecular formula C4H9Br reacts with aqueous KOH to give an alcohol. The rate of t

Compound ‘X’ with molecular formula C4H9Br reacts with aqueous KOH to give an alcohol. The rate of this reaction depends only on the concentration of the compound ‘X’. When an optically active isomer ‘Y’ o of the compound ‘X’ was treated with aqueous KOH solution, the rate of reaction was found to be dependent on concentration of compound ‘Y’ and aqueous KOH both. (a) Write down the structural formula of both ‘X’ and ‘Y’. (b) Out of ‘X’ and ‘Y’, which one will undergo racemisation and why? (c) Out of ‘X’ and ‘Y’, which one will form product with inversion of configuration and why? Class 12th Chemistry | Answer Key 2026 | CBSE Board | PYQ 2026 | Paper Code 56-1-1 | Set 1 | Q28 #pyqchemistry #prathamscienceacademyclasses #psaclasses #class12chemistrysyllabus #cbseboardquestionpaper #ncertchemistry #cbseclass12science #cbseboardchemistry#pyq2026#pyqchemistry#pyqs #answerkey #answerkey2026 #chemistryclass12th #pyqchemistryclass12 Class 12 Chemistry PYQ 2026