|| Thomas Calculus 12th & 13th edition exercise # 3.3 Question # 43-44(55-56) || Slope of tangent

Math tutor 665 Math tutor 665 Bsc # Bs # classes Math tutor 665 || Thomas Calculus 12th & 13th edition exercise # 3.3 Question # 17-28 || find derivative|| ||    • || Thomas Calculus 12th & 13th edition exe...   || Math tutor 665|| mathematics Math tutor 665## mathematics## How do you find the equation of a tangent? =================================== 1) Find the first derivative of f(x). 2) Plug x value of the indicated point into f '(x) to find the slope at x. 3) Plug x value into f(x) to find the y coordinate of the tangent point. 4) Combine the slope from step 2 and point from step 3 using the point- slope formula to find the equation for the tangent line. slope of tangent: ============= The slope of a curve y = f(x) at the point P means the slope of the tangent at the point P. We need to find this slope to solve many applications since it tells us the rate of change at a particular instant. [We write y = f(x) on the curve since y is a function of x. That is, as x varies, y varies also. =========================================================== || Thomas Calculus 12th & 13th edition exercise # 3.3 Question # 01-12 || Derivative by definition|| ||    • || Thomas Calculus 12th edition exercise #...   || #mathematics#math tutor 665 # The Definition Of The Derivative? Ans: In the first section of the Limits chapter we saw that the computation of the slope of a tangent line, the instantaneous rate of change of a function, and the instantaneous velocity of an object at x=a all required us to compute the following limit.