Part of a playlist on solids and surfaces of revolution: • Calculus II: Solids and Surfaces of Revolu... Volume of revolution using the disk method: y=1/x^3 revolved about the x-axis. Given the region bounded by y=1/x^3, x=1, x=3 and y=0 revolved about the x-axis, we find the volume by using the disk method. We start by labeling a disk at an arbitrary value of x, and we find the radius as (1/x^3)^2 and the thickness as dx. We express the volume element dV using pi*r^2*thickness. Next, we add up the volume elements using an integral. We integrate as x goes from 1 to 3 and evaluate the antiderivative across the limits of integration to obtain the volume of the solid of revolution.