Number System | Class 9 | Simplify Add Multiply Divide Real Numbers | Exercise 1.4 Solutions

Number System | Class 9 | Simplify Add Multiply Divide Real Numbers | Exercise 1.4 Solutions In this video I have explained in detail how to simplify different questions of addition subtraction multiplication and division of real numbers by solving example 12, 13, 14, 15 I have also given solutions of related question of exercise no 1.4 question number 2 Your Queries number system solution number system math solution number system ncert solutions links of videos of related topics Class 9 Maths Chapter 1 Number System Exercise 1.1solutions | what are different kinds of numbers In this video I have explained natural numbers, whole numbers, integers and rational numbers and difference between them    • Class 9 Maths Chapter 1 Number System Exer...   Number System | Class 9 | Real Numbers And Their Decimal Expansion | Exercise 1.2 | Exercise 1.3 solutions In this video I have explained real numbers and their types, identification of rational numbers and irrational numbers on the basis of their decimal expansion and some NCERT solutions    • Number System | Class 9 | Show Decimal Exp...   Number System | Class 9 | Show Decimal Expansion in p/q Form | Exercise 1.3 Solutions In this video I have explained how to convert a rational number which is either terminating or not terminating repeating can be converted into p/q form with three different case    • Number System | Class 9 | Real Numbers And...   Number System | Operations On Real Numbers Part 1| Solutions Exercise 1.4 In this video I have explained addition subtraction multiplication and division between two real numbers and what kind of results are obtained in a very detailed and simple method    • Number System | Operations On Real Numbers...   SOLUTIONS EXERCISE 1.4 QUESTION NO 2 (I) ( 3+√3)(2+√2) = 3(2+√2)+√3(2+√2) = 6+3√2+2√3+√6 (ii) (3+√3)3-√3) using identity (a+b)(a-b)= a^2-b^2 where a= 3 b=√3 = 3^2-√3^2 = 9-3 = 6 (iii) (√5+√2)^2 using identity (a+b)^2= a^2+2ab+b^2 where a=√5 b=√2 =√5^2+2(√5)(√2)+√2^2 = 5+2√10+2 = 7+2√10 (iv) (√5-√2)(√5+√2) using identity (a+b)(a-b)= a^2-b^2 where a= √5 b=√2 = √5^2-√2^2 = 5-2 = 3