JEE MAINS 7TH JAN 2020 SHIFT 2 - Which of these reactions are possible?

Consider the following reactions : (a) Cl + anhyd. AlCl3 (b) Cl anhyd. AlCl3 2(excess) Cl Cl Cl Cl Cl Cl dark (c) anhyd. AlCl3 CH2=CH–Cl CH=CH2 (d) anhyd. AlCl3 CH2=CH–CH2–Cl CH2–CH=CH2 Which of these reactions are possible? JEE | JEE 2019 | JEE main | JEE 2019 | JEE advanced | JEE mains 2019 | JEE main 2019 | JEE main january 2019 | 2019 JEE mains | JEE advanced 2019 | JEE | JEE 2020 | JEE main | JEE 2021 | JEE advanced | JEE mains 2020 | JEE main 2021 | JEE main january 2020 | 2020 JEE mains | JEE advanced 2020 | wbJEE | wbJEE 2020 | wbJEE 2020 exam date | JEE 2020 strategy | JEE mains 2020 strategy | JEE main exam 2020 | JEE preparation | Best books for JEE | Best Books for IIT JEE | JEE live daily | iit JEE | how to crack JEE | how to crack JEE advanced | JEE exam | JEE mains exam | JEE marks | IIT Preparation | JEE SOLUTION I JEE ADVANCED SOLUTION I JEE ADVANCED 2019 FULL SOLUTION I JEE 2019 FULL PAPER SOLUTION I IIT JEE PAPER 2 #CHEMSHIKSHA #IITJEEpreparations #JEEstrategies #IIT JEE QUESTION PAPER #IIT JEE 2019 SOLUTION #JEEMain2020 #JEEmains2020 #advance_2020 #howtocrackJEE2020