Class 9 Maths New NCERT | Chapter 2 | Polynomials | Exercise 2.3 | All Questions | Doubt Xpert

“Join India’s #1 Free Doubt Solving Platform – Doubt Xpert (also known as Doubt Expert) 🚀" 📘 Class 9 Maths - Polynomials (Exercise 2.3) Get 100% clarity on every question from Chapter 2 — solved step-by-step as per the New NCERT 2025 Syllabus. Learn easy formulas, fast tricks, and board-exam focused tips. 📌 Help Us Grow! 👍 Like the video if it helped you 🔔 Subscribe for more NCERT-based solutions 💬 Drop your doubts in the comments — we reply or make videos for them! 📤 Share with your friends who need help in Maths 📲 Need help with any doubt? Send your question as an image on Telegram/WhatsApp – get a free video/image solution from us! 🔗 *Join Us Here:* Telegram: https://t.me/Doubt_Xpert WhatsApp: +91-9643619960 Instagram:   / doubtxpert   Twitter: https://x.com/DoubtXpert Subscribe:    / @doubtxpert   📚 Questions Covered in This Video (Exercise 2.3 – Polynomials): Question 1. Find the remainder when x³ + 3x² + 3x + 1 is divided by (i) x + 1 (ii) x – 1/2 (iii) x (iv) x + π (v) 5 + 2x Question 2. Use the Factor Theorem to determine whether g (x) is a factor of p (x) in each of the following cases (i) p (x)= 2x² + x² – 2x – 1, g (x) = x + 1 (ii) p(x)= x³ + 3x² + 3x + 1, g (x) = x + 2 (iii) p (x) = x³ – 4x² + x + 6, g (x) = x – 3 Question 3. Find the value of k, if x – 1 is a factor of p (x) in each of the following cases (i) p (x) = x² + x + k (ii) p (x) = 2x² + kx + √2 (iii) p (x) = kx² – √2 x + 1 (iv) p (x) = kx² – 3x + k Question 4. Factorise (i) 12x² – 7x +1 (ii) 2x² + 7x + 3 (iii) 6x² + 5x – 6 (iv) 3x² – x – 4 Question 5. Factorise (i) x³ – 2x² – x + 2 (ii) x³ – 3x² – 9x – 5 (iii) x³ + 13x² + 32x + 20 (iv) 2y³ + y² – 2y – 1 #Class9Maths #NCERTSolutions #Polynomials #MathsMadeEasy #Exercise2 #NCERTBooks #ExamPreparation #BoardExams #CBSEboard #DoubtXpert #DoubtExpert #NCERT2025 #FreeDoubtSolving