JEE Advanced Physics 2015 Paper 1 #12 (#4) Angular Momentum

Visit http://ilectureonline.com for more math and science lectures! To donate: http://www.ilectureonline.com/donate https://www.patreon.com/user?u=3236071 Given: A ring of mass N and radius R is rotating with angular speed omega0 about a fixed vertical axis through its center with 2 point masses m at rest at the center. The 2 masses can move along the 2 mass-less rods with out friction. At an instant omega=(8/9)omega0 and m1, is at (3/5)R from the center. Find: Where is m2? Next video in this series can be seen at:    • JEE Advanced Physics 2015 Paper 1  #20  (#...