The major product (A) formed in the following reaction sequence is:

The major product (A) formed in the following reaction sequence is: (i) Sn, HCl (ii) Ac₂O, Pyridine (iii) Br₂, AcOH (iv) NaOH(aq) Theory: In the given reaction sequence, we can break down the steps as follows: Step 1 - Sn, HCl: The use of tin (Sn) and hydrochloric acid (HCl) indicates a reduction reaction. Here, the nitro group (-NO₂) is reduced to an amine group (-NH₂), resulting in the formation of aniline (C₆H₅NH₂). Step 2 - Ac₂O, Pyridine: Acetic anhydride (Ac₂O) in the presence of pyridine acts as an acetylating agent, introducing an acetyl group (-COCH₃) to the amine group, forming an acetylated product. Step 3 - Br₂, AcOH: In this step, bromine (Br₂) in acetic acid (AcOH) is used for electrophilic aromatic substitution. Bromine reacts with the ring, substituting a hydrogen atom at a position ortho or para to the amino group (-NH₂). Step 4 - NaOH(aq): The addition of aqueous sodium hydroxide (NaOH) results in the hydrolysis of any acyl group attached to the amine. This leaves behind the final product with a -NH₂ group and a -Br group at a specific position on the benzene ring. By analyzing the sequence of reactions, we can deduce the major product formed is the compound with the amine group at the para position to the bromine atom (after the electrophilic substitution reaction).