Shawcademy - MIT Integration Bee 2018 - Problem 3

Here, we are looking at the MIT Integration Qualifying Exam from 2018 and reviewing our integration techniques for difficult integrals. EDIT: When I say that changing the period doesnt change the result of the integral, this is only the case with the absolute value: ∫ |sin(2x)| dx = 2 ∫ sin(2x) dx u = 2x du/2 = dx leaving the integral as just: 2/2 ∫ sin(u) du which is evaluated the same as the others and results in an answer of 2 when evaluated from 0 to π. I hope that made sense to those of you who read the comments, otherwise just ask and I will make a new video about this or redo this video entirely. Thanks for watching - see you next time!