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(D^2+1)y = secx . tanx
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แสดงข้อมูลเพิ่มเติม 1
Find general solution of differential equation DY by DX + y sec x = tan x
If y = tan x + sec x,then prove that (𝐝^𝟐 𝐲)/(𝐝𝐱^𝟐 )=𝐜𝐨𝐬𝐱/(𝟏−𝐬𝐢𝐧𝐱)^𝟐 #cbse2026 #m
If y = tan x + sec x,then prove that (𝐝^𝟐 𝐲)/(𝐝𝐱^𝟐 )=𝐜𝐨𝐬𝐱/(𝟏−𝐬𝐢𝐧𝐱)^𝟐 #cbse2026 #m
Q) ) If y = tan x + sec x then prove that d^2 y/dx^2 = cos x / (1+sin x)^2 CBSE PYQ 2023CBSE 2026
VARIATION OF PARAMETERS(D²+1)y=secx-tanx
y"+y=secx, d^2y/dx^2+y=secx part3 #Variationofparameters L987
यदि y-secx-tanx हो तो सिद्ध कीजिए कि cosx(d^(2)y)/(dx^(2))=y^(2) | 12 | कठिन अवकलन | MATHS | NAV...
#MA3452 Variation of Parameter -2 || Solve d^2y / dx^2+y=secx by method of variation of parameters.
If y = tanx + secx then prove that d^2y/dx^2 = cosx ( 1 - sinx )^2
If y = secx - tanx , show that cosx d²y/dx² = y²
Solve: (D²+1)y= tanx using variation of parameters| d²y/dx² + y= tanx
#15 Variation of parameters method | solve (D^2+9)y= 1/(1+sin 3x) | solve (D^2+4)y=1/(1+cos 2x)
#14 Variation of parameters method | solve (D^2+4)y= tan 2x | (D^2+1)y=sec x tan x | (D^2+1)y=sec x
7. SOLVE ( D² + 1 )y = secx BY THE METHOD OF VARIATION OF PARAMETERS.
(D^2+1)y = secx . tanx
If `y=(tan x+secx)`, prove that `(d^(2)y)/(dx^(2))=(cosx)/((1-sinx)^(2))`
If `y=sec x-tanx`,show that `(cosx)(d^(2)y)/(dx^(2))=y^(2).`
If `y=tanx+secx` , prove that `(d^2y)/(dx^2)=(cosx)/((1-sinx)^2)`
