Differentiation: JEE Main 2021 PYQ 🔥| V(n) Method | Ramesh Chandra B.Tech IIT Kanpur

📚 In this video, we solve a JEE Main 2021 (Shift-II) problem from Differentiation: The problem states 🧠: Let f: S → S where S = (0, ∞) be a twice differentiable function such that f(x + 1) = x f(x). If g: S → R is defined as g(x) = ln(f(x)), then the value of | g''(5) - g''(1) | is equal to: Options: (a) 205 / 144 (b) 197/144 (c) 187/144 (d) 1 [16 March 2021, Shift - II] JEE Main 2021 Math PYQ Timestamp 0:00 - Introduction to Differentiation JEE Main 2021 PYQ. 0:16 - Dictation of the problem. 0:57 - Rewriting the given functional equation to have start. 1:20 - Taking natural log both side - Starting approach. 2:00 - Reframing the g(x+1) - g(x) and differentiating both side for desire result. 2:27 - Getting: g''(x+1) - g''(x) = - 1/x^2. 3:30 - V(n) - Method: getting Value of g''(5) - g''(1) = - 205/144. 4:49 - Correct Option is (A) 205/144. Key Concepts 💡📊: Functional equations & differentiation Recurrence relations in higher-order derivatives Logarithmic transformations to simplify problems class 12 maths differentiation important questions jee main differentiation questions differentiation jee pyq differentiation class 12 jee mains pyq method of differentiation class 12 jee pyq differentiation jee mains pyq 2024 differentiation class 12 important questions jee advanced differentiation questions Ideal for JEE Main & Advanced aspirants practicing PYQs on Differentiation. Strengthen your understanding of twice differentiable functions, logarithmic differentiation, and series summation.