If the tangent to the curve, y = x3 + ax – b at the point (1, – 5) is perpendicular to the line

If the tangent to the curve, y = x3 + ax – b at the point (1, – 5) is perpendicular to the line, –x + y + 4 = 0, then which one of the following points lies on the curve? || Let's IQRA JEE JEE Mains PYQ || Let's IQRA #jee_mains #calculus #iit #jee #pw #Lets_IQRA #limit #jee_mains #iitjee #pyq #letsiqra #jee_mains_pyq #pw #Let's_IQRA_JEE @Let's_IQRA_JEE Also You Search application of derivatives application of derivatives class 12 application of derivatives class 12 one shot class 12 maths application of derivatives applications of derivatives application of derivatives jee mains derivatives,application of derivatives jee application of derivatives one shot application of derivatives in one shot application of derivatives class 12 ncert maths class 12 application of derivatives cbse class 12 maths application of derivatives jee mains jee mains 2023 jee mains 2022 jee mains 2024 pyqs jee mains jee mains neha agrawal jee mains 2024 strategy pyq jee mains pyqs of jee mains 15 pyqs jee mains jee mains strategy jee mains 2023 date jee mains pyq marathon jee mains selection express jee mains pyqs for selection how to solve pyqs for jee mains jee mains pyq jee mains pyqs jee mains exam jee mains 2025 jee mains 2021 jee mains math jee mains paper jee mains maths

If the tangent to the curve, y = x3 + ax – b at the point (1, – 5) is perpendicular to the line

XIIAODQ048 _ If the tangent to the curve y = 𝑥3 + ax + b at (1, – 6) is parallel to the line

If the tangent to the curve y = x^3 + ax + b at (1,- 6) is parallel to the line

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