Thermodynamics Lecture 8 |Adiabatic Process| Reversible/irreversible process|JEE ADVANCED+MAINS| DPP
📘 Thermodynamics Lecture 8: Adiabatic Process (Complete Concept + Advanced Derivations) In this Thermodynamics Lecture 8, we explore one of the most important and frequently tested topics in Physics — Adiabatic Process. This lecture is designed to take students from absolute basics to advanced JEE level, making it extremely useful for JEE Main, JEE Advanced, NEET, Class 11, Class 12, and even Class 10 conceptual understanding. We begin by developing a clear physical understanding of the adiabatic process, explaining why no heat exchange (Q = 0) takes place between the system and surroundings. From there, we move step-by-step into the mathematical treatment and derivations, ensuring every formula is logically derived and not memorized. 🔹 What You Will Learn in This Lecture: ✔ Meaning and conditions of Adiabatic Process ✔ Difference between Isothermal and Adiabatic processes ✔ Work done in Adiabatic Process — full derivation from basic thermodynamic laws ✔ Relation: PV^γ = constant (with proper mathematical proof) ✔ Expression for work done, temperature change, and pressure relation ✔ Reversible Adiabatic Process — assumptions, derivation, and graphical analysis ✔ Irreversible Adiabatic Process — real life relevance and comparison ✔ Advanced numerical problems for JEE Main & JEE Advanced ✔ Common mistakes students make in adiabatic questions ✔ PYQ-based problem-solving techniques This lecture focuses heavily on conceptual clarity, so that students can solve any level of numerical or theoretical question without confusion. The derivations are explained in a slow, logical, and exam-oriented manner, making it perfect for self-study as well as revision before exams. If you are preparing for IIT JEE, NEET, or board exams, this lecture will strengthen your thermodynamics foundation and boost your confidence in solving PYQs and DPP questions. 📌 DPP: JEE PYQs on Adiabatic Process (Practice Problems) Q1. (JEE Advanced 2016) An ideal gas undergoes a reversible adiabatic expansion. Find the relation between temperature and volume. Q2. (JEE Main 2019 – April) Work done by an ideal gas during adiabatic expansion from (P₁, V₁) to (P₂, V₂). Q3. (JEE Advanced 2013) Compare work done in isothermal and adiabatic expansion for same initial conditions. Q4. (JEE Main 2020 – September) An ideal gas expands adiabatically. Calculate final temperature when pressure is reduced to half. Q5. (JEE Advanced 2018) A gas undergoes irreversible adiabatic expansion against constant external pressure. Find work done. Q6. (JEE Main 2021 – March) Find change in internal energy for an adiabatic process. Q7. (JEE Advanced 2015) Prove that PV^γ = constant for reversible adiabatic process. Q8. (JEE Main 2017) Calculate work done when one mole of gas expands adiabatically from V to 2V. Q9. (JEE Advanced 2020) Compare slopes of P-V curves for adiabatic and isothermal processes. Q10. (JEE Main 2022) Determine final pressure after adiabatic expansion given γ value. ➡️ (Students are advised to attempt these as a DPP after watching the lecture.) 🔍 SEO Hashtags (High Reach) #Thermodynamics #AdiabaticProcess #WorkDoneInAdiabaticProcess #ThermodynamicsForJEE #JEEPhysics #JEEAdvanced #JEEMains #NEETPhysics #Class11Physics #Class12Physics #Class10Physics #PhysicsDerivation #IITJEEPreparation #PhysicsConcepts #ThermodynamicsNumericals #ReversibleProcess #IrreversibleProcess
