Q) cos(sin^(−1) 3/5+sin^(−1) 5/13+sin^(−1) 33/65) is JEE #inversetrigonometricfunctionsclass12

JEE MAINS 2025 ( 28 Jan – SHIFT 1 ) Q) cos(sin^(−1) 3/5+〖 sin〗^(−1) 5/13+sin^(−1) 33/65) is equal to(a) 1(b) 0(c) 33/65(d) 32/65 JEE MAINS 2025 ( 28 Jan – SHIFT 1 ) #class11trigonometry #jee 2025 #jeemaths #jee2025 #jee2026 Insta I’d- Shivanggupta34 #diffrentiation #methodofdifferentiation DIFFERENTIATION JEE MAIN PLAYLIST LINK :: LIMITS , Continuity, differentiability playlist link :;    • Limits, continuity and Differentiability J...   JEE: Continuity L4 #jee2025exam #JEEshivangmathsacademy METHOD OF DIFFERENTIATION in One Shot: All Concepts & PYQs Covered | JEE Main & Advanced #JEE #JEE2025 #shivangmathsacademy #IIT #IIT2025 #JEE #methodofdifferentiation JEE 2025: Methods of Differentiation L1 #MethodOfDifferentiation #jee2025 #Continuity #JEE #JEE #JEEBatch #JEESeries l #jee2024 #Maths #Pyqs #JEEConcepts #OneShot #Differentiability #MethodOfDifferentiation Continuity at a point #JEEPreparation #JEEMain #JEEAdvanced #JEE2025 #JEEMathematics #OneShotJEE #CrashCourseJEE #JEEImportantQuestions #IITJEE #shivangmathsacademy #JEE #JEEMain #JEEmain2025 #JEEAdvanced #JEEAdvanced2025 #JEE2025 #JEEPreparation #JEE #Class12maths #DifferentiationClass12 #Differentiation Class 12 | One Shot | Marathon | JEE Main | JEE Advanced 2025 #differentiation of inverse Function #parametricfunction #parametricdifferentiation #impicitform #differentiationoflograthmicfunction Differentiation | Definition of Derivative | Geometric Interpretation of Derivative | Differentiability | Rules of Differentiation | Power Rule | Product Rule | Quotient Rule | Chain Rule | Derivative of Polynomial Functions | Derivative of Trigonometric Functions | Derivative of Exponential Functions | Derivative of Logarithmic Functions | Derivative of Inverse Trigonometric Functions | Higher Order Derivatives | Implicit Differentiation | Logarithmic Differentiati a tive of Hyperbolic Functions | Derivative of Inverse Hyperbolic Functio n | Applications of Derivatives | Tangent and Normal | Increasing and Decreasing Functions | Maxima and Minima | Rolle’s Theorem | Mean Value Theorem | L'Hôpital's Rule | Differentiability and Continuity | Differentiation of Composite Functions | Differentiation of Piecewise Functions | Differentiation under the Integral Sign | Differentiation of Multivariable Functions | Partial Derivatives | Directional Derivatives | Implicit Function Theorem | Optimization Problems | Related Rates Problems | Curve Sketching Using Derivat and Engineering. #higherorderderivatives ----------------------------------------------------------------------------------------------------------------------------------------------------------- Free IIT JEE coaching, Free JEd preparation, Best free lAdvanced, JEE Main #inversetrigonometricfunctionsclass12 #JEEMain #JEEAdvanced #Mathematics Trigonometric, logarithmic, and exponential functions, i#JEE2025 #JEEPreparation #JEEPreparationTips #JEEExam #JEEReady #JEE2025Preparation #JEEStudyTips #JEEAdvice #JEECrashCourse #JEEBooks #JEEPhysics #JEEChemistry #JEEMaths #JEEOnlineCoaching #JEEMockTests #JEEExamDay #JEESuccess #JEE2025Goals #JEEJourney #JEEAspiration Insta I’d- Shivanggupta Quadratic Equations JEE MAINS Class 11 :: https://www.youtube.com/playlist?list... ##pyqjee2023 #ir #functionalequation #je #jeepyq2022 # --------------------- #Maths #JEE # #JEE #JEEMaths #JEEExam #JEE2026 # | | SHIVANG Maths ACADEMY | SHIVANG Sir Maths #jee #jeemains #shivangmathsacademy #jee2024 #pyq #shivangmathsacademy #jeemaths #mathsjee #jeemain2023 #jeemainpyq2023 #jeemainpyq2022 #jeemainpyq2020 #class11maths #jeemain2024 #JEE2024 #4 April and January session #jeequest #jeemain #jeeadvanced #jeemain2025 #jeemain2024 #jee JEE MAINS 2025 JEE MAINS 2025 ( 3 April – SHIFT 1 )JEE ADVANCED 2025 (18 May – Paper 1 ) Q) For all 𝑥0, let 𝑦_1 (𝑥),𝑦_2 (𝑥), and 𝑦_3 (𝑥) be the functions satisfying . ■(&(𝑑𝑦_1)/𝑑𝑥−(sin𝑥)^2 𝑦_1=0,𝑦_1 (1)=5@&(𝑑𝑦_2)/𝑑𝑥−(cos𝑥)^2 𝑦_2=0,𝑦_2 (1)=1/3@&(𝑑𝑦_3)/𝑑𝑥−((2−𝑥^3)/𝑥^3 ) 𝑦_3=0,𝑦_3 (1)=3/5𝑒) respectively. Then lim(𝑥→0^+ ) (𝑦_1 (𝑥)𝑦_2 (𝑥)𝑦_3 (𝑥)+2𝑥)/(𝑒^3𝑥 sin𝑥)is equal to