Spring–Piston Ideal Gas Problem 🔥 | Temperature Increased 2.4× | JEE/NEET Physics

Is video me hum ek important thermodynamics numerical solve karte hain jisme ideal gas ek piston–spring system me enclosed hai. System ko heat kiya jata hai jisse temperature 2.4 times ho jata hai aur hume piston ke displacement ka pata lagana hota hai. Que: An ideal gas is enclosed in a container as shown in figure. The spring constant is 100 N/m, the area of the piston is 1 cm² and the length of the gas column is 100 cm. The compression of the spring is 10 cm. There is no friction between the walls and the piston. The whole system is heated to make the temperature 2.4 times the original temperature. Find the distance moved by the piston (in cm). Take atmospheric pressure = 105 Pa. If your answer is N fill the value of N/5. 👉 Concepts used: Ideal Gas Law Spring force & pressure relation Atmospheric pressure effect Equilibrium of piston 📌 Ye question JEE Main, NEET, CUET, Boards ke liye kaafi important hai. Aise hi conceptual numericals ke liye channel ko subscribe karein. 📚 Mohnish Gautam Physics – Concept se confidence tak #IdealGas #SpringPiston #Thermodynamics #jeephysics #neetphysics #mohnishgautamphysics #physicsshorts #jeepreparation #neet2025 #exampreparation #jee2025 #physicsquestions #neetpreparation