Gauss elimination method | Linear algebra | Part 2

📘 Solve by Gauss Elimination | Consistent System | Linear Algebra In this video, we solve the given system of linear equations using the Gauss Elimination Method. We form the augmented matrix, apply Elementary Row Transformations (ERTs), convert the system into upper triangular form, and perform back-substitution to obtain the unique solution. A very important problem type for VTU, BSc, BCA, Diploma, and many other university exams. 📝 Question Solve the following system of equations using Gauss elimination: 2x + y + 4z = 12 4x + 11y − z = 33 8x − 3y + 2z = 20 (We use Augmented matrix → ERTs → Upper triangular form → Back-substitution → Final answer.) 🎯 Who Should Watch This Video? (VTU – Latest CBCS/NEP) ✔ 1BMATS101 – Calculus and Linear Algebra (Module 3) ✔ 1BMATE101 – Differential Calculus and Linear Algebra (Module 5) ✔ 1BMATM101 – Differential Calculus and Linear Algebra (Module 4) ✔ 1BMATC101 – Differential Calculus and Linear Algebra (Module 5) ✔ BMATS101 / BMATE101 / BMATM101 / BMATC101 – Linear Algebra (Module 5) ✔ Ideal for BSc, BCA, Diploma and Degree students learning: • Gauss Elimination Method • Augmented Matrix and ERTs • Systems of Linear Equations • Echelon Form and RREF Useful for exam preparation, concept clarity, and last-minute revision across all universities. 🧠 Quick Solution Solution: (x, y, z) = (3, 2, 1) 💎 Support Us Join our channel and get access to exclusive perks 👇    / @officialmathematicstutor   #GaussElimination #LinearAlgebra #VTUMaths #EngineeringMathematics #SystemsOfEquations #MatrixMethods #ExamPrep