Class 10 Maths Chapter 12 | Surface Areas & Volumes | Ex 12.2 Q5 | NCERT #shikshaboard

Class 10 Maths Chapter 12 | Surface Areas & Volumes | Ex 12.2 Q5 | Lead Shots into Inverted Cone | NCERT Solution | Shiksha Board ⸻ Description: 🔵 Kya chhoti lead ki goliyon se ek bade cone ko fill kiya ja sakta hai? Kitni goliyan aayengi? Aaj hum exactly yahi solve karenge! Welcome to Shiksha Board, where Deepak Sahu explains Class 10 Maths Chapter 12 – Surface Areas and Volumes, Exercise 12.2 Question 5 with full concept clarity. In this video, we learn to calculate: ✅ Volume of one spherical lead shot ✅ Volume of inverted cone ✅ How many lead shots will fill the cone ⸻ 📘 Main formulas used: • Volume of Sphere (lead shot): V = \frac{4}{3}πr³ • Volume of Cone (inverted cone): V = \frac{1}{3}πR²H • Number of shots = (Volume of cone) ÷ (Volume of one sphere) ⸻ 🎯 Why this question is important? ✔ Frequently asked in board exams ✔ Tests real-life logic + 3D geometry ✔ Helps you understand volume conversion ⸻ 💡 By watching this video, you will not only solve the question but also understand the reasoning behind filling 3D solids with spheres — a common exam concept! ⚠️ Note: Exercise 12.2 contains only 8 questions. This is Question 5. ⸻ 👍 If you find this helpful: 🔔 Subscribe | ❤️ Like | 🔁 Share Comment “Cone + Sphere = Clear ✅” if you understood! ⸻ 🔍 Keywords (SEO): class 10 maths ex 12.2 q5, lead shots volume question class 10, inverted cone fill sphere question, surface areas and volumes, number of spherical balls in cone, ncert maths class 10, deepak sahu shiksha board, cone and sphere volume class 10 ⸻ 🏷️ Hashtags: #Class10Maths #Exercise12_2 #Question5 #SurfaceAreasAndVolumes #LeadShots #ConeAndSphere #3DGeometry #MathsInHindi #DeepakSahu #ShikshaBoard #NCERTSolutions #UKBoard #CBSE #BoardExam2025 #shikshaboard #class10maths #deepaksahu #ncertsolutions #cbse #maths #ukboard #ncertmaths #education #mathstricks