Prove that cot inverse (√1+sinx + √1-sinx)/√1+sinx - √1-sinx) = x/2

Prove that cot inverse (√1+sinx + √1-sinx)/√1+sinx - √1-sinx) = x/2 Prove that cot inverse root 1 + sin x + root 1 minus sin x by root 1 + sin x minus root 1 minus sin x is equal to x by 2 Prove that cot inverse { root (1+sinx) + root (1-sinx) upon root (1+sinx) - root (1-sinx) } = x/2 #inverse_trigonometric_function #bitwise_tutor