CE-17 | Wheatstone Bridge and Meter Bridge Balancing Condition based NEET & JEE Questions

CE-17 | Wheatstone Bridge and Meter Bridge Balancing Condition based NEET & JEE Questions

Part -17 | 12th Current Electricity | Wheatstone Bridge and Meter Bridge Balancing Condition based NEET & JEE Questions | Akash Sir Physics Timeline of Questions👇 00:00 | Introduction 00:25 | NEET 2022 & JEE_A Wheatstone bridge is used to determine the value of unknown resistance X by adjusting the variable resistance Y as shown in the figure. For the most precise measurement of X, the resistances P and Q: 01:57 | JEE 2022 & NEET_Current measured by the ammeter (A) in the reported circuit when no current flows through 10Ω resistance, will be __ A. 06:25 | JEE 2020 & NEET_Four resistances of 15Ω, 12Ω, 4Ω & 10Ω respectively in cyclic order to form Wheatstone’s network. The resistance that is to be connected in parallel with the resistance of 10Ω to balance the network is ____Ω. 09:49 | NEET 2006 & JEE_In the circuit shown, if a conducting wire is connected between points A and B, the current in this wire will: 12:35 | NEET 2019 & JEE_The metre bridge shown is in balance position with P/Q = l_1/l_2 . If we now interchange the positions of galvanometer and cell, will the bridge work? If yes, what will be balanced condition? 13:58 | JEE 2024 & NEET_The resistance per centimeter of a meter bridge wire is r, with XΩ resistance in left gap. Balancing length from left end is at 40cm with 25Ω resistance in right gap. Now the wire is replaced by another wire of 2r resistance per centimeter. The new balancing length for same settings will be at: 18:17 | JEE 2008 & NEET_Shown in the figure below is a meter-bridge set up with null deflection in the galvanometer. The value of the unknown resistor R is: 20:45 | NEET 2024 & JEE_The given circuit shows a uniform straight wire AB of 40cm length fixed at both ends. In order to get zero reading in the galvanometer G, the free end of J is to be placed from B at: 23:31 | JEE 2022 & NEET_A meter bridge set up is shown in the figure. It is used to determine an unknown resistance R using a given resistor of 15Ω. The galvanometer (G) shows null deflection when tapping key is at 43cm mark from end A. If the end correction for end A is 2 cm then the determined value of R will be __ Ω. 26:50 | JEE 2017 & NEET_In a meter bridge experiment resistances are connected as shown in the figure. Initially resistance P = 4Ω and the neutral point N is at 60cm from A. Now an unknown resistance R is connected in series to P & the new position of the neutral point is at 80cm from A. The value of unknown resistance R is: 30:31 | JEE 2018 & NEET_On interchanging the resistances, the balance point of a meter bridge shifts to the left by 10 cm. The resistance of their series combination is 1 kΩ. How much was the resistance on the left slot before interchanging the resistances? #asdphysics #asdphysicsacademy #akashsirphysics #physicswallah #asd #asdacademy #asdsirphysics #physics #neet #jeemains #neetpreparation #physicsneet #physicsfun #physicsclass #neetwallah #neetquestions #jeemainsquestions #viralvideo #youtubevideoviral #ammeter #voltmeter #galvanometer #resistance #current #resistance #currentelectricity #currentelectricityclass12 #potential_difference #wheatstone #wheatstone_bridge #wheatstonebridge #metrebridge #meterbridge #cell Follow Us: Facebook:   / asdphysics   Instagram:   / asd_physics_academy   Telegram:https://t.me/asdphysicsacademy Twitter:   / asdphysics   WhatsApp:https://bit.ly/3VSi3uF