Cbse Class 10 Triangles Exercise 6.3 Question 2 to 4 in Tamil / Chapter 6 New Syllabus / Kalvikan

Chapter 6 Triangles Exercise 6.3 Question no 2, 3, 4 in Tamil / Cbse Class 10 Maths New Syllabus/ Ncert Book Question / Kalvikan 👉 Class 10 Triangles :    • Class 10 Triangles   2. In the given figure, ∆ODC ~ ∆OBA, ∠BOC = 125° and ∠CDO = 70°. Find ∠DOC, ∠DCO and ∠OAB. 3. Diagonals AC and BD of a trape∠ium ABCD with AB || DC intersect each other at the point O. Using a similarity criterion for two triangles, show that OA/OC=OB/OD∙ 4. In the given figure, QRQS=QTPR and ∠1 = ∠2. show that ∆PQR ~ ∆TQR. #kalvikan #navimaths #kalvikantnsyllabus #trigonometry #cbsemathsintamil #class10 #triangle #triangles #exercise #chapter6 ------- Like | Share | Subscribe ------- 🙏 Thanks From Kalvikan 🙏