POLYNOMIALS- EX- 2.3- Q8 TO Q14 - NCERT MATHS EXEMLAR SOLUTIONS-CLASS-9

POLYNOMIALS- EX- 2.3- Q8 TO Q14 - NCERT MATHS EXEMLAR SOLUTIONS-CLASS-9 EX-2.3 Short Answer Type Questions Question 8: If p (x) = x2 – 4x + 3, then evaluate p(2) – p (-1) + p ( ½ ). Question 9: Find p(0), p( 1) and p(-2) for the following polynomials (i) p(x) = 10x – 4x2 – 3 (ii) p(y) = (y + 2)(y – 2) Question 10: Verify whether the following are true or false. (i) -3 is a zero of x – 3 (ii) -1/3 is a zero of 3x+1 (iii) -4/5 is a zero of 4 – 5y (iv) 0 and 2 are the zeroes of t2 – 2t (v) -3 is a zero of y2 +y - 6 Question 11: Find the zeroes of the polynomial in each of the following, (i) p(x)=x – 4 (ii) g(x)= 3 – 6x (iii) q(x) = 2x – 7 (iv) h(y) = 2y Question 12: Find the zeroes of the polynomial p(x)= (x – 2)2 – (x+ 2)2. Question 13: By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial x4 + 1 and x-1. Question 14: By remainder theorem, find the remainder when p(x) is divided by g(x) (i) p(x) = x3-2x2 - 4x-1, g(x)=x + 1 (ii) p(x) = x3 -3x2 + 4x + 50, g(x)= x – 3 (iii) p(x) = 4x3 – 12x2 + 14x 3, g(x)= 2x – 1 (iv) ‘p(x) = x3 6x2 + 2x- 4, g(x) = 1 -(3/2) x exercise 2.3,exercise 2.3 class 9 maths exemplar,exercise 2.3 class 9 exemplar solution,ex 2.3 polynomials class 9 ncert exemplar,ex 2.3 polynomials exemplar by GOLDY SIR,ex 2.3 class 9 exemplar,class 9 maths exercise 2.3,ex 2.3 class 9 maths exemplar,ex 2.3 polynomials class 9 maths,ex 2.3,2.3 exemplar,exercise 2.3 live,ncert maths ex 2.3,ex 2.3 class 9 maths,ncert class 9 ex 2.3,class 9 chapter 2 ex 2.3,chapter 2 exercise 2.3,ex 2.3 solution class 9