An electron enters electric field of \( 10^{4} \mathrm{~V} / \mathr...

An electron enters electric field of \( 10^{4} \mathrm{~V} / \mathrm{m} \) perpendicular to the field with a velocity of \( 10^{7} \) \( \mathrm{m} / \mathrm{s} \). Find the vertical displacement of electron after 2 milliseconds. Mass of electron \( =9 \cdot 1 \times \) \( 10^{-31} \mathrm{~kg} ; \) charge on electron \( =1.6 \times 10^{-19} \mathrm{C} \). 📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live