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Find dy/dx when x = a (cos t + log tan (t/2)), y = a sin t
Find dy/dx when x = a (cos t + log tan (t/2)), y = a sin t
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Find dy/dx when x = a (cos t + log tan (t/2)), y = a sin t
x=a(cos t + log (tan t/2) ) , y=a sin t , Find dy/dx
If ` x=a (cos t +log (tan ((t)/(2)) )) ,y =a sin t ,then (dy)/(dx) =`
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`x=a(cos t + log tan t/2), y =a sin t`
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यदि ` x = a ( cos t + log tan "" ( t ) / ( 2 ) ) , y = a sin t`, तब ` dy / dx `
x = a(cos t + log tan t/2), y = a sin t
#Parametricdifferentiation Method Problems if x=a[cost+log(tant/2)], y=asint then Find dy/dxory’
In the curve `x= a (cos t+ log tan(t/2))`,` y =a sin t`. Show that the portion of the tangent b...