Class 9th Theorem 8.8 Proof | Midpoint Theorem

This video presents a proof of a triangle theorem. What does the theorem say? According to the theorem, the line segment joining the midpoints of two sides of a triangle is parallel to the third side. Key points of the proof in the video: Construction and setup: To begin the proof, a line is drawn parallel to the third side. Congruency: We prove two triangles (e.g., AFE and FDC) are congruent. Use of angles: To prove congruence, the video uses the following angles and sides: Midpoint: Side AF is equal to side FC because F is the midpoint. Alternate angles: The equality of alternate angles is used because of parallel lines. Vertically Opposite Angles: The equality of vertically opposite angles formed by two intersecting lines is also used. Parallelogram: After proving the triangles are congruent, it is proved that the quadrilateral EDCB is a parallelogram. This is possible because its opposite sides (CD and EB) are equal and parallel. Conclusion: Since EDCB is a parallelogram, side ED will be parallel to side BC, and thus EF is also proved to be parallel to BC. This video is useful for students who want to understand Theorem 8.8 of Class 9 Geometry in detail. #Class9Maths #MidpointTheorem #Parallelogram #GeometryProof #TribhujKiPramey #slevelcc Note from slevelcc 🕊️: This video may contain some factual or data errors. We urge you to re-verify the information before making any significant use of it. If you find any errors, please let us know in the comments—we would appreciate your cooperation. Thank you!