Ratio of Moment of Inertia: Sphere with Spherical Cutout | Parallel Axis Theorem | NEET Physics

Here we solve the NEET question: Q: A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. Find the ratio of the moment of inertia of the smaller sphere to that if the rest part of the sphere about the Y-axis? Key Concepts Covered: Parallel Axis Theorem: I = I_cm + Md² Subtraction method for cutout: I_cut = I_large - I_small (adjusted for axis) If you found this helpful, like, share, and subscribe for more physics problems solved step-by-step! Comment your doubts below. #MomentOfInertia #ParallelAxisTheorem #NEETPhysics #JEEPhysics #RotationalMotion #PhysicsProblems #SphereCutout