Class 10 Triangles || Chapter 6 || Exercise 6.3 | Question 13 and 14 | Cbse New Syllabus | Kalvikan

Class 10 Triangles || Chapter 6 || Exercise 6.3 | Question 13 and 14 | Cbse New Syllabus | Kalvikan

Cbse Class 10 Maths Chapter 6 Triangles Exercise 6.3 Question no 13 and 14 in Tamil / Book Questions New Syllabus / Kalvikan 👉 Class 10 Triangles :    • Class 10 Triangles   13. D is a point on the side BC of a triangle ABC, such that ∠ADC = ∠BAC. Show that CA² = CB.CD. 14. Sides AB and AC and median AD of a triangle ABC are respectively proportional to sides PQ and PR and median PM of another triangle PQR. Show that ∆ABC ~ ∆PQR. #kalvikan #navimaths #kalvikantnsyllabus #trigonometry #cbsemathsintamil #class10 #triangle #triangles #exercise #chapter6 ------- Like | Share | Subscribe ------- 🙏 Thanks From Kalvikan 🙏