The sum of the areas of two squares is `640 m^(2)`. If the difference in their perimeters be 64 m,

The sum of the areas of two squares is `640 m^(2)`. If the difference in their perimeters be 64 m,

The sum of the areas of two squares is `640 m^(2)`. If the difference in their perimeters be 64 m, find the sides of the two squares.