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If u=x^2tan-1y/x-y^2tan-1x/y show that ∂^2u/∂x∂y=(x^2-y^2)/((x^2+y^2)
If u=x^2tan-1y/x-y^2tan-1x/y show that ∂^2u/∂x∂y=(x^2-y^2)/((x^2+y^2)
แสดงข้อมูลเพิ่มเติม 1
If u=sin^-1 x+y /√x + √y show that x du/dx + ydu/dy = 1/2 tan u.
If z=x^2 tan^-1(y/x)-y^2 tan^-1(x/y). Then ∂^2Z/∂x∂y is?||If z=x2tan−1(yx)−y2tan−1(xy)
Partial Differentiation |Multivariable Calculus|z=x²tan⁻¹(y/x)–y²tan⁻¹(x/y),∂²z/∂x∂y=(x²–y²)/(x²+y²)
Partial Differentiation | Multivariable Calculus | u = tan⁻¹(y/x), ∂²u/∂y∂x = ∂²u/∂x∂y
Partial Differentiation || 𝑺𝒊𝒏^(−𝟏) [(𝒙^𝟐+𝒚^𝟐)/(𝒙+𝒚)] || vtu maths || Dr Prashant Patil
Partial Differentiation || 𝒛=𝒕𝒂𝒏^(−𝟏) (𝒚⁄𝒙) || VTU maths || Dr Prashant Patil
If z=x^2tan-1(y/x) -y^2tan-1(x/y), prove that del^2z/delydelx=x^2-y^2/x^2+y^2
solve u= tan^-1 [(x^3+y^3)/(x-y)] EULERS PARTIAL DERIVATIVE
If u=x^2 tan^-1(y/x) - y^2 tan^-1(x/y) Prove Ә^2u/ӘxӘy= (x^2-y^2)/(x^2+y^2) Partial Derivative
PARTIAL DIFFERENTIATION IN HINDI LECTURE 7
partial differentiation
If `u=x^2tan^(-1)(y/x)-y^2tan^(-1)(x/y)`,prove that `(del^2u)/(delxdely)=(x^2-y^2)/(x^2+y^2)`
19. Partial Derivatives | Problem#2 | Most Important Problem | Partial Differentiation
