Please download the mobile app from the link below https://bit.ly/37l8M5G Join Telegram: https://t.me/joinchat/RnBH5Bm7XL3qMOyG Join our Whatsapp group: https://chat.whatsapp.com/KQ44L1usAAb... Call us at 9993336391 or visit www.ascentgateacademy.com for complete course details 00:00:12 - A work piece of 1000 mm length and 300 mm width is machined by planning operation with a feed of 0.3 mm/stroke. The machine tool executes 10 double strokes per minute. The planning time for a single pass is 00:04:16 - In a surface broaching process, a broach having 5 mm pitch and cut per teeth 0.05 mm is used for reducing the thickness by 6 mm. If the length of the work piece is 50 mm and the cutting speed is 0.05 m/s, the time required/pass in seconds is 00:07:59 - A gear with 84 teeth is to be machined using a milling process with indexing. The index plate has the following four hole circles: 36, 38, 42, 48. the change gear ratio required is 00:10:55 - In an ideal orthogonal cutting experiment, the cutting speed V is 1m/s. The rake angle of tool is 5 and shear angle is known to be 45. Applying the ideal orthogonal cutting model, consider two cutting planes PQ and RS close to each other. 00:17:12 - A straight-teeth horizontal milling cutter is shown in the figure. It has 4 teeth diameter (D) of 200 mm. The rotational speed of the cutter is 100 rpm and the linear 4 given to the workpiece is 10 mm/min The width of the workpiece (w) is 100 m and the entire width is milled ina single pass of the cutter. The cutting force/tooth is given by F = Kt,w, where specific cutting force K 10 N mm2, w is the width of cut, and t, is the uncut chip thickness. The depth of cut (d) is D/2, and hence the linear fe d assumption of 1 is invalid. 00:23:11 - A 1 mm thick cylindrical tube, 100 mm in mm in diameter, is orthogonally turned such that the entire wall thickness of the tube is cut in a single pass. The axial feed of the tool is 1 m minute and the specific Cutting energy (u) of the tube material is 6 J/mms. Neglect contribution of feed force towards power. The power required to carry out this operation is kW. 00:29:21 - Under orthogonal cutting condition, a turning operation is carried out on a metallic workpiece at a cutting speed of 4 m/s. The orthgonal rake angle of the cutting tool is 5°. The uncut chip thickness and width of cut are 0.2 mm and 3 mm, respectively. In this turning operation, the resulting friction angle and shear angle are 45° and 25°, respectively. If the dynamic yield shear strength of the workpiece material under this cutting condition is 1000 MPa, then the Cutting force is _N (round off to one decimal place) 00:34:10 - In a pure orthogonal turning by a zero rake angle single point carbide cutting tool, the shear force has been computed to be 400 N. f the cuting velocity, V = 100 m/min, depth of cut, t= 2.0 mm, feed, so = 0.1 mm/revolution and chip velocity. V= 20 m/min, then the shear strength T of the material will be (round off to two decimal places). MPa 00:40:26 - An orthogonal cutting operation is performed using a single point cutting tool with a rake angle of 12° on a lathe. During turning, the cutting force and the friction force are 1000 N and 600 N, respectively. If the chip thickness and the uncut thickness during turning are 1.5 mm and 0.75 mm, respectively, then the shear force is N. [Round off to two decimal places] 00:47:21 - Bars of 250 mm length and 25 mm diameter are to be turned on a lathe with a feed of 02 mm/rev. Each regrinding of the tool costs Rs. 20. The time required for each tool change is 1 min. Tool life equation is given as VTO.2 24 (where cutting speed Vis in m/min and tool life Tis in min). The optimum tool cost per piece for maximum production rate is Rs 00:54:20 - In a turning process using orthogonal tool geometry, a chip length of 100 mm is obtained for an uncut chip length of 250 mm. The cutting conditions are cutting speed = 30 m/min, rake angle = 20°. The shear plane angle is degrees round off to one decimal place). 00:56:04 - A through hole is drilled in an aluminum alloy plate of 15 mm thickness with a drill bit of diameter 10 mm, at a feed of 0.25 mm/rev and a spindle speed of 1200 rpm. If the specific energy required for cutting this material is 0.7 N-m/mmÅ¡, the power required is__W 01:03:17 - Taylor's Tool Life Equation is used to estimate the life of a batch of identical HHS twist drills by drilling through holes at constant feed in 20 mm thick mild steel plates.In Test 1 a drill lasted 200 holes at 300 rpm.The Maximum number of holes that can be made by another drill from the above batch at 200 rpm is 01:08:01 - An orthogonal cutting operations is being carried Out in which uncut thickness is 0.010 mm, cutting speed is 130 m/min, rake angle is 15 and width of cut is 6 mm. It is observed that the chip thickness is 0.015 mm, the cutting force is 60 N and the thrust force is 25 N. The ratio of friction energy to total energy is