Numerical Problems | Chapter 10 | 10th Class Physics | NBF New Book FBISE Session 2025-2026

For latest videos, click on the following link: https://whatsapp.com/channel/0029VaGr... 1. Convert specific heat of water 𝟒𝟏𝟖𝟎𝑱〖𝒌𝒈〗^(−𝟏) 𝑲^(−𝟏) into units of 𝑱𝒈^(−𝟏)°𝑪^(−𝟏). 2. Calculate amount of heat given to 25kg of water to increase its temperature by 𝟓𝟎℃. 3. A half kg block of an unknown metal is heated from 𝟑𝟎℃ to 𝟖𝟎℃, requiring 𝟏𝟗𝒌𝑱 of heat energy. (a) Calculate the specific heat capacity of the metal. (b) If the same metal block is heated from 𝟖𝟎℃ to 𝟏𝟐𝟓℃, how much additional heat energy would be needed? 4. Calculate the change in temperature of 5 litre of water if it absorbs 𝟖.𝟒𝑴𝑱 of heat energy? (𝑼𝒔𝒆 𝒕𝒉𝒆 𝒔𝒑𝒆𝒄𝒊𝒇𝒊𝒄 𝒉𝒆𝒂𝒕 𝒐𝒇 𝒘𝒂𝒕𝒆𝒓 =𝟒𝟐𝟎𝟎𝑱〖𝒌𝒈〗^(−𝟏) 𝒌^(−𝟏)) 5. In a container, 100g of water at 𝟖𝟎℃ is mixed with 𝟐𝟎𝟎𝒈 of warer at 𝟐𝟎℃. What will be the final temperature of the mixture, assuming no heat loss to the surroundings (and container)? (Use specific heat capacity of water is 𝟒𝟐𝟎𝟎𝑱〖𝒌𝒈〗^(−𝟏) 𝑲^(−𝟏) or 𝟒.𝟐𝑱𝒈^(−𝟏) 𝑲^(−𝟏)) 6. A 𝟐𝟎𝟎𝒈 piece of an unknown solid cylinder is heated to 𝟏𝟏𝟎℃ and then placed into a calorimeter containing 𝟐𝟎𝟎𝒈 of water at 𝟐𝟎℃. Calorimeter has a mass of 𝟔𝟎𝒈 and specific heat capacity of 𝟎.𝟗𝑱/𝒈℃. The final temperature of the system (solid, water & calorimeter) is 𝟑𝟓℃. Assume no heat is lost to surroundings. Calculate specific heat capacity of solid. 7. A hot steel rod is cooled by plunging it into cold water, as shown in Fig. The steel rod has a mass of 𝟑𝒌𝒈 and is initially at a temperature of 𝟒𝟓𝟎℃. It cools to 𝟓𝟎℃ when placed in the water. The specific heat capacity of steel is 𝟒𝟔𝟎𝑱〖𝒌𝒈〗^(−𝟏)°𝑪^(−𝟏). Calculate the thermal energy (heat) lost by the steel rod as it cools to 𝟓𝟎℃.