Let f ( x  ) = | 8  𝒙^𝟐  𝒔𝒊𝒏 𝒙  𝒑  − 𝟏 | ,  where p is a constant . The  value of p 𝒇^, ( 0 ) = 1 is

Let f ( x ) = | 8 𝒙^𝟐 𝒔𝒊𝒏 𝒙 𝒑 − 𝟏 | , where p is a constant . The value of p 𝒇^, ( 0 ) = 1 is

CBSE PYQ 2024 Q) y = cos^-1 (root x ) , find dy/dx CBSE 2026 Inverse Trigonometric PYQ 2025 Maths for Class 12 #cbse2026 #maths#cbseboard #Class 12 Inverse Trigonometric Function CBSE 2026 #cbse #cbseboard #cbseclass12 #CBSE2026 #MATHS #inverse_trigonometric_function class12 #CBSEPYQ2025 #CBSE #CBSE2026 #CBSE2026 #MathsCBSE #BoardExamPrep #Class12Maths #TrigonometryCBSE #InverseTrigCBSE #MathsRevision #CBSEMaths #Class12Boards #CBSEStudy #BasicsCBSE PYQ 2025 ) Q) CBSE PYQ 2025 ) Q) CBSE 2026 Inverse Trigonometric PYQ 2025 Maths for Class 12 #cbse2026 #maths#cbseboard CBSE PYQ 2024 CBSE PYQ 2024 CBSE PYQ 2024 CBSE PYQ 2023 CBSE PYQ 2023 CBSE PYQ 2023 CBSE PYQ 2025 CBSE PYQ 2025 Q) CBSE PYQ 2025 matrix and determinants class 12 objective CBSE PYQ 2025 CBSE PYQ 2025 CBSE PYQ 2025 CBSE PYQ 2025 CBSE PYQ 2024 CBSE PYQ 2025 CBSE PYQ 2023 CBSE PYQ 2025 Q) CBSE PYQ 2023 CBSE PYQ 2025 CBSE PYQ 2024 CBSE PYQ 2024 Q) CBSE PYQ 2022 CBSE PYQ 2021 CBSE PYQ 2019 Q) CBSE PYQ 2021 CBSE PYQ 2023 CBSE PYQ 2025 CBSE PYQ 2023 differentiation of inverse trigonometry class 12 inverse trigonometric functions class 12 CBSE PYQ 2025 CBSE PYQ 2022 Q) CBSE PYQ 2021 #maths CBSE 2026 differentiation CBSE PYQ 2025 Let f ( x ) = | 8 𝒙^𝟐 𝒔𝒊𝒏 𝒙 𝒑 − 𝟏 | , where p is a constant . The vale of p for which 𝒇^, ( 0 ) = 1 is R 1 0 1 𝒙=𝟎 #maths CBSE 2026 differentiationx #maths CBSE 2026 differentiation #maths CBSE PYQ 2024 #maths CBSE 2026 Differen #maths #maths CBSE 2026 Differentiation CBSE PYQ 2025 #maths CBSE 2026 Differentiation PYQ 2024